Determine the pH of the solution of 1M hydrocyanic acid (HCN) in water. The pKa for HCN is 9.31?



Answer:
HCN ↔ H+ + CN-

Ka = 10^-9.31 = 4.90 * 10^-10
4.90*10^-10 = [H+][CN-]/[HCN]

let [H+] = [CN-] = x
[HCN] = 1

4.90 *10^-10 = x^2/1

x = sqrt (4.90*10^-10) = 2.21*10^-5

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