How do you write equations for these?
2. Solutions of cobalt (II) nitrate and sodium hydroxide are mixed.
3. Ethene gas is burned in air.
4. Equal volumes of equimolar solutions of phosphoric acid and potassium hydroxide are mixed.
5. Excess hydrochloric acid is added to a sollution of diamminesilver (I) nitrate.
6. Solid sodiuim oxide is added to distilled water.
7. A strip of zinc is added to a solution of 6.0-molar hydrobromic acid.
Answer:
In response to your edit, it's a redox reaction. Since both of your anions are chloride, the cadions aren't going to "switch" like normal. Instead, they're going to go to their other oxidation states. Tin has oxidation states of +2 and +4, and iron has oxidation states of +2 and +3. Therefore, tin will go to +4, and iron will go to +2, making it the reaction you posted in your edit.
1. SnCl2+FeCl3 + H20 = SnO2 + FeCl2
2. Co(NO3)2 + 2NaOH = Co(OH)2 + 2NaNO3
3. CH2=CH2 + 3O2 = 2H2O + 2CO2
4. KOH + H3PO4 = KH2PO4 + H2O
5. HCl + Ag(NH3)2NO3 = AgCl + NH4Cl + NH4NO3
6. Na2O + H2O = 2NaOH
7. Zn + 2HBr = ZnBr2 + H2
1 may be wrong -I haven't been to your class or done the experiment
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