Chem. prob help of equilibria of slightly soluble ionic compounds?

the molar solubility of M2X is 5.2x10-5M. what is the molaroty of each ion? How do u set up the calculation to find Ksp? what assumption must you make about the dissociation of M2X into ions? why is the calculated Ksp higher than the actual value?

Answer:
molarity of each ion is the coefficiebt times the molar solubility
M= 2*5.2x10^-5=1.4x10^-4 M
X=5.3x10^-5

Assume one molar solution. Absolutely imperative because otherwise you cannot do any calcs

Ksp=([M]^2[X])/[M2X]

so

((1.4x10^-4)^2(5.2x10^-5))/(1-...

Ksp= 1.019x10^-12

The assumptions that need to be made is the M2X goes to ions, not other compounds. Ksp is calculated based upon ions, not secondary compounds or polymers. M2X could go to M4X2, this would not be represented in the Ksp calc. The Calculated Ksp is higher for this reason.

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