What is the percent ionization of a 0.0382 M aqueous solution of cyanic acid, HCNO (Ka = 3.5E-4)?
Answer:
Use the Ostwald dilution law. It states
α2c = Ka
α2 = Ka/c
α2 = 3.5*10^-4/(0.0382)
α2 = 0.009162304
α = 9.572*10^-2 = 9.572 %
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