Write a balanced chemical equation for the reaction between sulfuric acid and potassium hydroxide.?
Answer:
Sulphuric acid formula = H2SO4(aq)
Potassium hydroxide formula = KOH(aq)
This is a neutralisation reaction, an acid and a base.
Hence acid + base --> salt + water:
H2SO4(aq) + KOH(aq) --> K2SO4(aq) + H2O(l) (not balanced)
* the charge onH2SO4(aq) + 2KOH(aq) --> K2SO4(aq) + H2O(l) the SO4 ion is 2-, and the charge on a K+ ion is 1+ so we need 2 potassiums on the right to create a neutral salt.
Hence to balance:
H2SO4(aq) + KOH(aq) --> K2SO4(aq) + H2O(l)
2 K on the right, we need 2 on the left as well:
H2SO4(aq) + 2KOH(aq) --> K2SO4(aq) + 2H2O(l)
Oxygens are balanced so the whole thing is balanced.
4 H on the left, so we need 4 on the right:
The equation of the reaction is:
H2SO4 + KOH -----> K2SO4 + H2O
The balanced equation is :
H2SO4 + 2KOH -----> K2SO4 + 2H2O
Since 2 potassium is on te right side, 2 moles of KOH are needed. This now makes it 4H and 6 O on the left hence 2 moles of water is required to balance the equation.
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