Le chatelier's principle?

C+H20+heat <-->CO+H2

1) if you increse carbon what will happen to the reaction?
2) if you decrease H2o what will happen to the reaction?
3)if you increase pressure what will happen to the reacton?

thanks so much!!! :]

Answer:
I agree with Dr. Shane for the first two:
1) left
2) left
However for 3, there are fewer moles of gas on the left (1- water vapor) than there are on the right (2- carbon monoxide and hydrogen gas)
Dr. Shane was right in that it will shift to fewer moles of gas, but incorrect in evaluating the number of moles on each side.
3) left
REmember whatever u do, it trys to undo.
1. there will be a shift to the right(c is on the left)
2. there will be a shift to the right(H2O is on the left)
3. pressure(number of moles) - there is 2 on the left and 2 on the right so NOTHING WILL HAPPEN TO THE PRESSURE. however, when u increase pressure it shifts to the side with less moles(coefficientes)
1) shift to the right (products)
2) shift to the left (reactants)
3) shift to the left (or in general, the side with the fewest gas molecules)

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