For the reaction 2NO2(g) ì N2O4(g) at 325 K equilibrium is established when [N2O4] = 0.020M and [NO2] =?
5.8 ´ 10-3
2.9 ´ 10-1
5.4 ´ 10-1
1.7 ´ 102
Answer:
2NO₂ ←→ N₂O₄
Therefore the equilibrium constant in terms of concentrations is:
K = [N₂O₄] / [NO₂]²
= [0.02] / [0.0108]²
= 171.47
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