An HCl solution has a pH of 3.10, what is the [OH-] in this solution?

7.9 x 10^-18 M
1.3 x 10^-11M
7.9 x 10^-4 M
1.3 x 10^3 M

Answer:
pOH = 14 - 3.10 = 10.9
[OH-] = 10^-10.9 = 1.3 x 10^-11 M
pOH = 14 - 3.10=10.9

[OH-] = - Antilog 10.9=1.258425X10^ -11 ~= 1.3X10^ -11 M

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