You determine the pH of a solution to be 4.07. Therefore the [OH-] is?



Answer:
pH + pOH = 14

4.07 + pOH = 14 ==> pOH = 9.93

pOH = -log[OH-]

so [OH-] = 10-pOH = 10-9.93 = 1.17 *10^-10
ph=4.07 means that [H+]=1E-4.07
[OH-]=1E-(14-4.07)=1E-9.93 mol/l
10^-(14-4.07)

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