How many atoms of carbon are in 4.00x10^-8 grams of C3H8.?
Answer:
4 x 10^-8g of C3H8
No. of moles = (4 x 10^-8)/ (36 + 8)
Moles = 9.1 x 10^-10 g/mol
1 mole of substance contains 6.02 x 10^23 molecules:
Hence in 9.1 x 10^-10 moles there are: 5.47 x 10^14 molecules.
1 molecule contains 3 carbon atoms, hence the total number of carbon atoms = 3 x (5.47 x 10^14) = 1.64 x 10^15 C atoms.
Due to the small value of the mass and the answer, I suspect a typo somewhere either in the answers or the question. You are correct if this is the question being asked.
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