Chemistry Help?

Milk of magnesia is an aqueous suspension of magnesium hydroxide [Mg(OH)2] used to treat acid indigestion. Calculate the volume of a 0.035 M HCl solution (a typical acid concentration in an upset stomach) needed to react with two spoonfuls (approximately 10mL) of milk of magnesia [at 0.080 g Mg(OH)2/mL].

Answer:
You've got 10 mL of suspension.

That means you've got 0.80 g of magnesium hydroxide.

The molecular weight is 58.3 g/mol

0.80 g / (58.3 g/mol) = 0.0137 mol Mg(OH)2

Mg(OH)2 + 2 HCl = MgCl2 + 2 H2O (balanced!)

So you need 2 x 0.0137 mol of HCl = 0.0274 mol HCl.

Your solution has 0.035 mol per liter, so

0.0274 mol HCl / (0.035 mol/L) = 0.784 L = 784 mL.

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • Mass-Volume Relationships Problem Question?
  • What are the max numberof APT molecules that may be produced from a molecule of glucose by aerobicresperation?
  • Which of the following does not contain hydrogen? (a)Water(b)common salt,or (c)sugar?
  • What happens when u add soda to alcohol?
  • Need help on this problem??
  • Please Help Me With My Organic Chemistry!!!?
  • Is feces (human or otherwise) flammable and/or explosive?
  • What is the difference between active and inactive ingredients in a product?
  • What volume (mL) of a 0.20 M...?