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5SO2 +2MnO 4- +2H2O -> 5SO4 2- + 2Mn 2+ + 4H+
Calculate the number of grams of SO2 in a sample of air if 7.37 mL of 0.00800 M KMnO4 solution are required for the titration.
Answer:
0.00737 L of an 0.00800 M solution is 5.90E-05 mol of permanganate.
5.90E-05 mol MnO4 x (5 mol SO2 / 2 mol MnO4) = 1.47E-04 mol of SO2.
Molecular weight of SO2 is 32 + 32 = 64 g/mol.
1.47E-04 mol of SO2 x 64 g/mol = 9.43E-03 g of SO2.
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