Titration of 35.0 mL a calcium hydroxide solution to the endpoint requires 16.41 mL of 0.050M HCl soltion?

What is the molar quantity of OH− in the 35.0 mL of solution?

Answer:
Here is the balanced reaction

Ca(OH)2 + 2HCl >> CaCl2 + 2H2O

0.050Moles/L*0.01641L=8.2X10-4... HCl. Now there is a 2 to 1 ratio so you have

8.2x10-4 moles HCl*(1mole Ca(OH)2/2molesHCl)=

4.1x10-4molesCa(OH)2

Now you have 2 moles of OH- for every mole of Ca(OH)2
therefore

4.1x10-4*2=8.2x10-4 moles of OH-

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Titration of 35.0 mL a calcium hydroxide solution to the endpoint requires 16.41 mL of 0.050M HCl soltion?

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