I would like to balance this equation:?
I don't understand please help! I need to know how to write it correctly.
Answer:
C3H8(g)+O2(g) --> CO2(g)+H2O(g)
Now we have 3 carbons on the left, so we need 3 on the right:
C3H8(g)+O2(g) --> 3CO2(g)+H2O(g)
We have 8 hydrogens on the left, so we need 8 on the right:
C3H8(g) + O2(g) --> 3CO2(g) + 4H2O(g)
Now all we have to do is balance the oxygens there are 10 on the right so we need 10 on the left:
C3H8(g) + 5O2(g) --> 3CO2(g) + 4H2O(g)
Simple as that.
3 carbons at left so you need 3 carbons at right.
C3H8 + O2 -> 3CO2 + H2O
now balance the hydrogens
C3H8 + O2 -> 3CO2 + 4H2O
now backcalculate the oxygen demand:
C3H8 + 5O2 -> 3CO2 + 4H2O
for hydrocarbons that is the fastest and easiest way to do it.
When balancing the combustion reactions of hydrocarbons, you can use the formula:
CxHy + (x + y/4)O2 => xCO2 + (y/2)H2O
its very easy to balance these type of oxidation of hydrocarbons.
first balance the carbon(C) atom fully by putting the exact molecule number before CO2. here in left C=3. so we must put 3 before CO2 to balance.
then balance the number of H completely with the H20. here in left H=8. so we must put 4 before H2O to balane 8 atoms of H both side.
now simply count the numbers of O atom in the right side its (3*2+4*1) or 10.balance it by putting a 5 on the left side of O2.
that is C3H8 + 5O2= 3CO2 + 4H2O
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