Please help..thermodynamics question?

Consider a system consisting of 2 mol of gas molecules at 110 kPa is compressed reversibly and adiabatically until temperature reaches 150 K. Given that its molar constant-volume heat capacity is 26.5 JK-1mol-1, calculate q, w, dU and dH.

Answer:
We need the initial temperature of the gas molecules to solve this.

I have assumed that temperature to be 298 K, the standard room temperature.

The work done (w)= nCv(T2 - T1) = 2 * 26.5 * 188 = +9964 Joules
The plus sign indicates that the work is done by the system on the surrounding.

In an adiabatic change, the change in internal energy of the gas is equal to the negative of the work done, as no heat is supplied to the gas
So dU = -9964 Joules

q and dH are both zero in an adiabatic change.

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