I have a problem set to complete for chemistry tomorrow, and I'm stuck on the last problem! Please help!?

Calculate the molarity of H2S(aq) which would be produced in 2.00 liters of water if 0.015 grams of Ag2S react to completion according to this reaction: 3Ag2S(s)+2Al(s)+3H2O(l) yields 6Ag(s)+Al2O3(s)+3H2S(aq). Assume all of the H2S produced remains in the solution as H2S(aq).

Okay, so I'm trying to convert the silver sulfide into moles, then convert those moles o moles of the hydrogen sulfide, and then divide that by the number of liters to get the molarity...but the number seems way too small! What am I doing wrong?!

Answer:
if you find the limiting reagent then you would have the moles of silver sulfide in the end reaction and then divide that by the total liters of solution in the end then youll get molarity. Since there are two quantities you need to find the limiting reagent first.. i hope im helping you lol

ok, just a hint for you

a mole is Avogadro's number of molecules

6.023 x 10^23

just put everything into moles

then its moles/liter for molarity

The number will be very small. 0.015 g of Ag2S is only 6.05x10^-5 moles. Since the ration of moles og Ag2S to H2S is 1:1 and you have 2 liters of solution, the answer is 3.02x10^-5 M.

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I have a problem set to complete for chemistry tomorrow, and I'm stuck on the last problem! Please help!?

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