having the following ion concentrations at 298 K.
[H+] = 4.0 x 10-2 M
[OH-] = 7.9 10-6 M
Answer:
pH = -log [H+]
So for your first equation, it'll be
pH = -log (4.0 x 10^-2 M)
pH = 1.4 (remember to keep your significant figures)
For the second one, it'll be
pOH = -log (7.9 x 10^-6 M)
pOH = 5.1
pH = 14- 5.1
Thus, pH = 8.9
pH = -log[H+]
thats pH = minus log to base 10 of the hydrogen ion concentration,
So, pH = 1.40
Hope this helps
Ashley
pH = -log[H+]
pOH = -log[OH-]
pH= 7- pOH
Hope it helps
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