A pot containing 3.00 kg of water is sitting on a hot stove and the water is stirred violently by a mixer that does 8.0 kJ of mechanical work on the water. The temperature of the water rises by 4.00°C. What quantity of heat flowed into the water from the stove during the process?
Answer:
Qstove + Qmixer = mc(delta T)
Qstove = mc(delta T) - Qmixer
Qstove = (3000g)(4.184J/g-C)(4C) - (8,000J)
Qstove = 50,208J - 8000J
[ Qstove = 42,208 joules ]
Use the Formula C = Q/m x delta T
4.1841kJ/mol = Q/3kg x 4
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