How many millilites of 0.4000M NaOH are required to completely neutralize 20.0 ml of 0.200M HCI?
Answer:
NaOH + HCl ----> NaCl + HOH (salt and water)
mL ? 20ml 0.2M
0.2MHCl = moles/0.02L = 0.004 MolesHCl
0.4NaOH = 4.0 mol/L = 0.1L = 100mL
huh?
2
mL x M = mL x M
20 x 0.200 = mL x 0.400
mL = 10
this is true because 1 mole of NaOH reacts with 1 mole of HCl and mL x M = millimoles of a substance. (Liters x M = moles of a substance).
The balanced equation is:
NaOH + HCl --> NaCl + H2O
So, you have a 1 mol to 1 mol ratio for Sodium Hydroxide reaction with Hydrochloric acid.
0.4000 M means there are that many mols of NaOH per liter of the solution.
0.200 M means there are that many mols of HCl per liter of solution.
So, the HCl is half as strong as the NaOH, therefore it only takes 10.0 mL of this NaOH solution to do the job.
(0.4000mol/L)(x L) = (0.200mol/L)(0.0200L)
x = 0.0100 L or 10.0 mL
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