A gas with a volume of 525mL at a temperature of -25 degrees celcius is heated to 175 degrees celcius. what is
volume of the gas if pressure and number of moles are held constant?
Answer:
The formula for that is V1 * T2 = V2 * T1. V1 is the first volume. V2 is the second volume. And so on with the temperatures. This is Charles' Law that states as temperature increases, volume also increases.
your answer is 948.39 mL. You always have to convert Celcius to Kelvin by adding 273. do (525 mL * 448 K)/248.
Hope that helped
Hey topspin, you have -25, not +25
V1/T1 = V2/T2
V2 = V1T2/T1
V2 = 525mL x 448K / 298K
V2 = 789mL
Charle's law. The volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure.
V1/V2 = T1/T2....V1 x T2 = V2 x T1 (T in Kelvin)
T1 = 248K ...T2 = 448K
V1 = 525mL..V2 = ?
V2 = (525 x 448) ÷ 248
..... = 235,200 ÷ 248
New volume = 948.4mL
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Answer:
The formula for that is V1 * T2 = V2 * T1. V1 is the first volume. V2 is the second volume. And so on with the temperatures. This is Charles' Law that states as temperature increases, volume also increases.
your answer is 948.39 mL. You always have to convert Celcius to Kelvin by adding 273. do (525 mL * 448 K)/248.
Hope that helped
Hey topspin, you have -25, not +25
V1/T1 = V2/T2
V2 = V1T2/T1
V2 = 525mL x 448K / 298K
V2 = 789mL
Charle's law. The volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure.
V1/V2 = T1/T2....V1 x T2 = V2 x T1 (T in Kelvin)
T1 = 248K ...T2 = 448K
V1 = 525mL..V2 = ?
V2 = (525 x 448) ÷ 248
..... = 235,200 ÷ 248
New volume = 948.4mL
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