At constant temperature the pressure on a 6.0 liter sample of gas is increased from 1.0 atm to 2.0 atm. cont.?

What is the new volume of the gas sample?
.33 liters
.67 liters
1.5 liters
3.0 liters

Answer:
Aplying the law of Boyle-Mariotte:

P1V1=P2V2

1atm*6L=2atm*?

?= 1atm*6L/2atm

?= 3.0 Liters
Use P1/V1 = P2/V2

1/6 = 2/x
x = 12 L

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