Could any one help me with Simplefying this boolean expression for X= (A.B'+C)'.((A.C)'+B')?



Answer:
Karnaugh maps are your friends.

(A.B'+C)'.((A.C)'+B') simplifies to:

(C+(A.B'))'

which can be transformed using deMorgan's Theorem to:

C'.(A'+B)

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