How to find capacity of triangular shaped tanks??
Answer:
Sounds like your tanks have bases in the shape of isoceles triangles - two of the three sides are the same length.
The fomula quoted by others (b*h/2) is for use when the 'height' of the triangle has been measued. In your case that would be the distance from the short side to the opposite apex.
A little geometry shows that if your 'base' is the shortest side and we call that 2b and call the other sides l - both equal length, and finally call the distance from base to apex 'd' then
l^2 = d^2 + b^2
d = sqrt (l^2 - b^2)
area = b * sqrt (l^2 - b^2)
volume = h b sqrt (l^2 - b^2)
first triangle has l = 1350, b = 415, h = 300
second one is l = 600, b = 205, h = 300
vol 1 = 159936472 mm^3 = 160 l
vol 2 = 34679402 mm^3 = 34.7 l
miltiply length and width (the legs of the tiangle) and divide that By 2, then multiply that by the depth
a triangle is a two dimensional object so has zero volume.
The volume is given by the area of the triangular base * depth of the tank.
Large tank: 300 * (1285 * 830) /2 cubic mm = 159982500
There are a million cubic millimetres in a litre
Volume of large tank is approx 160 litres.
Small tank 300 * (564 * 410) /2 = 34686000
About 34.7 litres
(The 1285 and the 564 refer to the distance from the middle of the short side to the opposite 'corner')
Hope that helps.
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