What would be the volume of bend cylinder?
Answer:
Let's work it out from First Principals. Let A be the cross sectional area of the cylinder. Let R be the radius from the center of the bend to the centerline of the cylinder. Take a slice, dT (where T is theta). It's slightly wedge shaped, but if you start with the first side you drew, and drew a line parallel to it thru the intersection of the centerline of radius R and the second side, you would find that the extra area added inside of the centerline is exactly equal to the reduction in area outside it. So we can say that it's volume = it's length * A It's length is a part of the circumference of the circle of radius R, and the total circumference = 2*Pi*R so the length of dT is dT * R. Integrate R dT from zero to Pi/2 and get the total length = Pi * R / 2 That's the arc length of a quarter circle. If you multiply that times the cross sectional area of the cylinder you get the volume of the bend cylinder (assuming a 90 degree bend) So, V = A * Pi * R / 2 where A is cross sectional area of the pipe and R is the radius of the bend.
What's a "bend" cylinder?
you need to work out the volume of a torus.
then work out what percentage of 360 degrees the bend is, and multiply the volume by this.
http://grapevine.abe.msstate.edu/~fto/to...
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