If I have a quad-2 NOR gate IC, how would I go about implementing an AND gate and an OR gate?
Thanks.
Answer:
You get an inverter from a NOR by wiring the inputs together.
You can get an OR gate by putting an inverter on the output of a NOR gate (i.e., re-inverting the output).
You can get an AND gate from putting an inverter on each input of a NOR gate. This comes from deMorgan's theorem (see sources).
Generally, you solve these problems by manipulating a boolean expression using boolean logic (aka boolean algebra). See sources. As mentioned by someone else, Karnaugh maps can also be used to simplify logic, though these become difficult to use for more than 4 variables.
NOR gates are universal gates, because they can be used to form all three basic gates: NOT, OR, and AND. These three basic gates can be used to make any combinational logic circuit. NAND gates are also universal gates.
Without giving you the direct answer, use truth tables. It is not all that hard. This is a great site to help you to learn how to solve the problem. And if you want, it will show you the answer as well.
http://www.kpsec.freeuk.com/gates.htm...
Truth tables will be of little help. It will still be somehwat of a trial and error process. Truth tables are just a tool to see what the standard gate functions are or a specific function a person wants to implement. To implement the function one must convert the truth table to a Boolean algebra function and minimize. Either that or use a Karnaugh Map which allows for a graphical solution of sorts if you don't like doing algebra. Just do a search for Karnaugh Maps and Boolean algebra. They are more scientific.
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