How much does 5 gallon of water weigh ?

1 gallon of water = 3.78541178 litre
5 gallon of water = 18.9270589 litre

1 litre of water has an index mass of ~1.000


1litre of water = 1.000kg

18.9270589 litre of water = 18.9270589 kg

5 gallon of water = 18.9270589 kg

Or in pounds,

= 18.9270589 x 2.20462

= 41.726972592118 pounds

Hope that helps!!
How about 5 gallons :)
roughly 41 lbs
Water weighs 8 pounds per gallon. 5 gallons would weigh 40 pounds.
42.85 lbm at 4°C
Units are such that one liquid ounce of water weighs one ounce-weight. 16 ounces in a pound.

An American gallon is 4 quarts of 32 ounces each = 4 times 2 pounds = 8 pounds. 5 US gallons weighs 40 pounds (plus the weight of the container, I guess)

An imperial gallon is 4 quarts of 40 ounces each (4*2.5 = 10 pounds); 5 Imperial gallons = 50 pounds.
41.727 pounds.
1 Gallon is roughly 4.5l of water (British.Standards)
1l of water weighs 1kg,
so 5 Gallons x 4,5 = 22,5l of water which weighs roughly 22,5kg.
If you using American Standards then multiply by 3,5 to get the ammount of litres.
About 22.3 kg. It depends on the water!
15 kg
A pint of water weighs 1.3lb. A gallon weighs 10.4lb. 5 gallons weigh 41.6lbs
There is a saying that "A pint's a pound the world around." There are 2 pints in a quart and 4 quarts in a gallon (check the supermarket dairy shelves). Therefore, a gallon of water weighs 8 pounds and 5 gallons weigh forty pounds. To lose one pound by weight reduction, you must lose a pint (or pound) of flesh or excess liquids. Losing forty pounds is like losing 5 gallons of flesh!
if you want the exact weight then you should have given the atmospheric conditions.

assuming @STP, density water= 1000 kg/m3

since 3.78 li = 1 gallon, density is mass over volume

by dimensional analysis,
mass=density x volume

mass therefore = (1000 kg x 3.78 x 5)/1000 li/1 m3
mass in kg = 18.9 kg

mass in lbs = 18.9 kg x 2.2 lb/1 kg
= 41.58 lbs

if you want exact weight, refer to my good friend robert perry he has a book called Perrys chemical engineers handbook youd be able to find the actual density of water at any given atmospheric condition ( temp.)

The answers post by the user, for information only, does not guarantee the right.

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