How do you calculate pressure based on volume and temperature?
Answer:
Reference: http://www.efunda.com/materials/water/st...
Vapor pressure of saturated water (or saturated steam) at 150 C = 69.01 psi absolute.
The quantity (10 kg) of water does not matter. Water will remain in liquid state only if the pressure is above 69.10 psi absolute. (psi = pounds per square inch)
Hence pressure inside tank is 69.01 psi absolute or (69.01-14.69) = 54.32 psi gauge. It can have higher pressure than this, in which case it is called superheated steam.
PV=nRT
Pressure = P
V= Volume
n= moles
R= gas law constant
T= temperature
make sure you use the right units
Water boils at 100 degrees C, so what one has is a cubic meter of gas at 150 degrees C. Chemists use the "universal gas law" to calculate pressure : PV = nrT. P is pressure, V is volume, T is temperature "n" is amount and "r" is a constant term. Amount is calculated in terms of "moles". A mole is a certain weight of some substance based on its molecular weight. This is the sum of the atomic weights, and for H2O it is 18 grams. Therefore, 10,000 grams would equal 556 moles of water. All one has to do at this point is to make sure the units are the same as the ones used in the constant term "r".
At a given temperature, the volume in the gases is inversely proportional to the pressure. According to this, it is possible to figure the variations of pressure and volume in a gas when one of these variables change, mathematically can be expressed V1 P1 = V2 P2
V1 and P1 corresponds to the initial volume and pressure respectively in a given gas once one of the variables change its original conditions being V2 or P2 , in order to keep the balance in the equation, the other variable vary natural and proportionally maintaining the equality in the equation.
According to Ideal Gases law, (V1 P1) /T1 = (V2 P2 )T2 = nR
n= mol (22.4 lts) at 1 atm. 0ºC
R= Constant of Gases o,082 (atm L) / K.mol
At 100°C steam pressure = 1atm.
Using Gay Lussac's Law. At constant volume (the rigid tank), the Pressure of a gas (steam) is Directly Proportional to its Temperature).
Temperature Increase <===> Pressure Increase.
Mass of water isn't required.
Initial Pressure = 1 atm...Initial Temp. = 100°C (273K)
...Final Temp. = 150°C (423K).
P1.1atm x T2.423K = P2 x T1.273K
P2 = 423 ÷ 273 = 1.55atm = 1,178mmHg.
Millerain J...I'm surprised at you, details and conversions like this should remain in your memory indefinitely.
I still remember them from my College years ...50 years ago.
p1v1=p2v2 & the relationship of temperature and v, i cannot remember, I take thermodynamics when i was 2nd year and now i am 4th year student.
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