Led in wall plug?
Answer:
Some night lights for kids bedrooms are LED's. I would take one of these and use the parts. They are not expensive.
LED's will work on ac because they are diodes and will rectify to dc although its supposed to reduce their life.
The real problem is the voltage. An LED requires a very small voltage (around 6v). This means that a resistor in series to drop the voltage would have a large volt drop across it. Since power equals v squared over r, the power rating of the resistor would need to be very high and impractical. Therefore transformers have to be used.
No, because the led runs on DC voltage, not AC voltage.
To plug an led into an 110 V AC outlet and make it work, you will need transformer to reduce the voltage, a diode to convert the AC voltage to DC voltage, this will be the only way you will be able to plug into an AC out let and make an led light with out blowing.
John R is more or less correct, except that you could eliminate the transformer if you didn't mind a low efficiency result.
Connect a 50K, 1W resistor in series with the LED;
then connect a 1 uF, 200V capacitor in parallel with the previous;
then connect a 200 ohm resistor and series diode, e.g. 1N4002, in series with the previous combo.
Make sure the forward direction of both diodes is pointed in the same direction. You will be dropping a lot of voltage across the 50K resistor, so it will be inefficient.
Buy it already assembled.
Try Lowe's, Home Depot, Fry's Electronics or even Walmart or Kmart.
Here's one
well first you need to know the operating current of the led. then you need to select the proper resistor. using the formula r=e/i, and next you need to select a series diode with at least a 200 volt piv. which is like a 1N2004 or higher, since the peak to peak voltage of a 120 volt circuit is much higher than the average voltage like about 187 volts peak to peak potential difference . but a 1ma device would require about 120 k ohm, 1/8 watt resister. but as the resistance is decreased and the current is increased so must the wattage of the resister, using the formual p= i x e to calculate the wattage of the resistor needed. and you could even use a full wave rectifier, if desired.
"ywait' gives a very good answer. Newark Electronics is a good source for such devices as well. These lamps are composed of several LED's, and some other components. They came into common use in the mid 1990's.
I am going to guess that the others based their responses on 1 LED being powered by 110Vac, which without the needed voltage drop to a safe level would cause a nice, but brief explosion.
yeah just buy them
i've got LED lights with photoelectric sensors in them. they switch on during the night and its only 0.005w so i dont even mind switching them off throughout the night. i've got one in every room... kitchen, living, and staircase landing. its bright enough for you to see your souroundings but not enough to read the label of your meds.
:))
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