a circuit with a voltage source of 10V, a resist of 1 Megohm and a cap of 1 Microfarad. what is the voltage ROUGHLY after 1 second and 2 second. I said it would be 6V after 1 second and 8V after 2 seconds. is this correct?
Answer:
You're correct, 1Mx1u=1sec time constant
Your talking DC voltage, right?
Yes. You are correct.
The voltage across a capacitor charging through a resistor from zero intital volts is given by V(1 - e^(-t/RC)). In your case RC = 1 sec, so at 1 second the voltage would be 10(1 - e^(-1)) which is 6.32 volts. At 2 seconds the voltage would be 10(1 - e^(-2)) which is 8.64 volts.
The answers post by the user, for information only, FunQA.com does not guarantee the right.
More Questions and Answers:
What is the difference between a bs and a ce number?
Where are the production means made?
Ideas for building a fallout shelter?
IWLM carrier in elctronics?
What is a double-deck lift?
Enter robot wars?
How strong is a 1 TESLA?
Which is the worst engineering...which is tough and has no scope....!!?
How do I get static electricty at my power so I can shock people?