Find the remaining six trigometric functions,if sine = 3/4?
Answer:
sin= y\r
cos= x\r
tan= y\x
and csc, sec and cot are all reciprocals of those so...
csc= r\y
sec= r\x
tan= x\y
so therefore, if sin= 3\4= y=3 r=4 and x=x
cos= x\4
tan= 3\x
and csc= 4\3
sec= x\3
and tan= 3\x
I think. 8]
First we find the 3rd side, since sine is opposite over the hypotenuse the third leg is length X
x^2 + 3^2 = 4^2
or x=sqrt(7)
Sin = 3//4
Cos = sqrt(7)/4
Tan = 3/sqrt(7)
Sec = 1/Sin
Csc = 1/ Cos
Cot = 1/Tan
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