A6 – 2a3b3 + b6?
How to factor this??????
Answer:
Assume A^3 = x and B^3 = y.
The equation then reduces to X^2- 2x*y + y^2
which is equal to (x-y) * (x-y)
Converting x, y into A & B, the answer becomes
(A^3 - B^3) * (A^3 - B^3)
If all else fails use the quadratic equation.
Pretend that a^3 equals x, and that b^3 equals y.
Then, you should recognize!
(a^3 -b^3)^2
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Answer:
Assume A^3 = x and B^3 = y.
The equation then reduces to X^2- 2x*y + y^2
which is equal to (x-y) * (x-y)
Converting x, y into A & B, the answer becomes
(A^3 - B^3) * (A^3 - B^3)
If all else fails use the quadratic equation.
Pretend that a^3 equals x, and that b^3 equals y.
Then, you should recognize!
(a^3 -b^3)^2
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