Explain the relationship among voltage,current,and resistance.?
Answer:
Other answers have correctly given the "Ohm's Law" formula, but it seems that the questioner is also asking for a physical description.
The current (I) is the amount of electrons that flow. The voltage (V or E) is the amount of push given to them. The harder you push, the more current you drive. However, each material allows electrons to flow through it at different rates. This is the "resistance" (R). For moderate amounts of current flow through a metal like copper, this resistance remains nearly the same even as you change the voltage. This is the "Ohm's Law" regime of current flow.
Voltage = Current multiplied by Resistance (V=IR)...
= Volts
Current = Voltage divided by Resistance (I=V/R)...
= Amps
Resistance = Voltage divided by Current (R=V/I)...
= Ohms
v=IR, I=V/R AND R=I/V where v=voltage, i=current and r=resistance
v=i*r,i=v/r,r=v/i
Current= Voltage/Resistance OR
I=V/R
A current in a resistor equals the voltage divided by resistance.
Basically, the more the resistance of a conductor (wire) the less the current. Similarly the more the voltage, the more the current.
Yup, all the math relates to Ohm's law: E = I * R
It's handy to consider electricity in terms of water flow in a closed loop plumbing system. The pump is your power source (Like the electrical utility or a battery). The stronger your pump, the more water that will flow in the system. This is like Volts (V) aka Electromotive Force (EMF or E). The more pressure your pump develops (More Volts), the more water you move.
The amount of water that flows past a given point in the system each second is like electrical currrent. Flow in gallons/sec in the plumbing would be in Amperes (Amps or A) of electrical current, which is I in Ohm's law. One Coulomb of charge passing a given point in the circuit in 1 second is current flow (I) of 1 Ampere.
Resistance can be thought of as a restriction in the piping system in the plumbing analogy, it slows down the water flow through it and causes a drop in pressure meaured across it. In electricity, a resistance reduces current flow and causes a voltage drop across said resistance. A very high resistance is like a restriction in the pipe that has only a tiny opening for water flow. Not much water gets thru, and the pressure on the downstream side is very low compared to the pressure on the upstream side (Voltage drop).
Back to Ohm's law, solved for I:
I = E / R
I (Current flow) increases when E (Volts or pressure) increases. I decreases when R (Resistance) increases.
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