Homework help, please?!!? Really appreciate it, thanks!!?

The frequency of a vibrating string is inversely proportional to its length. If a string 30 cm long has a frequency of 40 Hz, what is the frequency of a string 24 cm long?


A.
50 Hz


B.
42 Hz

C.
36 Hz

D.
32 Hz

Answer:
f = k*1/l, where k is a proportionality constant.
40 = k*1/30, so k =1200
f = 1200*1/24
f = 50 Hz
f1/f2=l2/l1
40/f2=24/30
f2=40*30/24=50HzletterA. answer
Try creating a fraction with a common denominator, then you can figure out the inverse of the number substituting the new value.
The frequency of a vibrating string is inversely proportional to its length. If a string 30 cm long has a frequency of 40 Hz, what is the frequency of a string 24 cm long?
Products are equal:
(30)(40) = (24)(n)

n=50

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