Bearing Surveying?

Can anyone help with this bearing question Thanks
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Answer:
You must first compute the bearing of AE
Ihope you can follow my method. Ifirst convert the given azimuths to bearings:

AB: S (180-164d35)E= S15d25'E
BC: N83d18'40"E
CD: N38d26'10"E
DE: S(180-159d50')E=S20d10'E

now compute the sum of the eastings and northings from A to E keeping in mind that S and W are negative

Eastings:
sin(15d25')100+sin(83d18'40")1...

26.58+.9932(135.67)+.6216(128.
26.58+134.75+79.64+38.39=

Eastings = 279.36

Northings:
-cos(15d25')100+cos(83d18'40")...

-.9640(100)+.1165(135.67)+.783...

-96.4+15.81+100.36-104.51=

Northings =-84.74

Thus we knwo that point E is 279.36 east of A and 84.74 south.


the bearing E to A will be Arctan(279.36/84.74)=3.29667
=73.12554 deg =N73d7'32"E

the azimuth will be 180--73d7'32"= 106d52'28"

to get the azimuth of AP subtract the given angle:

106d52'28"-67d45'10" = 39d7'18"

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