A person notices a mild shock if the current along a path through the thumb and index finger exceeds 84 µA. Calculate the maximum allowable voltage without shock across the thumb and index finger with a dry-skin resistance of 5.0 x10^5 .
Answer:
I= 8.4*10^-5
R=5.0*10^5
V=I*R= 8.4*10^-5*(5.0*10^5)
=8.4*5.0= 42 volts
Use Ohm's law: V = IR
Set V = (84μA)(5.0x10^5Ω)
The voltage before shock will be less than this so the solution should read V < (84μA)(5.0x10^5Ω)
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