How do I calculate the air flow in a 12" diameter nozzle in cubic feet per minute?

I have a 24 foot diameter tank 32 feet in height. In order not to calapse the tank how large of a diameter vent nozzle (at the top of the tank) do I need if I am pumping out water (at the bottom of the tank) at a rate of 1950 gpm?

Answer:
3.1415927*12^2*32= 14476 cu ft --pool

u have a 12" diameter (1 foot) nozzle --?? thats a big nozzle

--re write the the question again in the right units
inner diameter in inches and length of pipe in to the pool and out side the pool (exit)

Misunderstood the question !

delta_bravo_1kilo@yahoo.ca
You are pumping 1950 gpm water from a tank and there is a 12"diameter vent. What is the air flow through the vent?

The air flow through the vent is equal to the volume of water displaced 1950 (gal/min) / 1 ft^3 water /7.481 gal=260.6 ft^3/min of air through the 12" vent. That is the flow 261cfm.

Flow =v*A
for a 12"D opening A=pi/4 ft ^2
the velocity through the 12 in opening is 261 cfm * 4 / pi = 332 ft per min, which does not seem excessive.

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